मान लीजिए कि $f$ इस प्रकार है कि प्रत्येक वास्तविक $x$ के लिए $f(-x) = -f(x)$ और $\int_{0}^{1} f(x) dx = 5$,तो $\int_{-1}^{0} f(t) dt = $

  • A
    $10$
  • B
    $5$
  • C
    $0$
  • D
    $-5$

Explore More

Similar Questions

$\int_{ - \pi /2}^{\pi /2} {\frac{{\sin x}}{{1 + {{\cos }^2}x}}{e^{ - {{\cos }^2}x}}dx} $ का मान ज्ञात कीजिए।

$\int_{0}^{\pi} \frac{x \tan x}{\sec x + \tan x} dx =$

$ \int_{-2}^{2} |x \cos \pi x| \, dx $ का मान ज्ञात कीजिए।

यदि ${u_n} = \int_0^{\pi /4} {{\tan ^n}x\,dx,} $ है,तो ${u_n} + {u_{n - 2}} = $

$\int_{-1}^1 \sin^5 x \cos^4 x \, dx$ का मान है

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo